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=5Y^2-12Y-9
We move all terms to the left:
-(5Y^2-12Y-9)=0
We get rid of parentheses
-5Y^2+12Y+9=0
a = -5; b = 12; c = +9;
Δ = b2-4ac
Δ = 122-4·(-5)·9
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-18}{2*-5}=\frac{-30}{-10} =+3 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+18}{2*-5}=\frac{6}{-10} =-3/5 $
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